Prime Number Formula XIX

p_n=1+\displaystyle\sum_{k=1}^{2 \cdot (\lfloor n\ln(n) \rfloor+1)}\left(2-\left\lceil \frac{1}{n} \cdot \left(1+\displaystyle\sum_{j=2}^k \left\lfloor\frac{\displaystyle\sum_{i=1}^j \left\lfloor \frac{1}{\gcd(i,j)} \right\rfloor+2}{\displaystyle\sum_{i=1}^j \left(\frac{j}{i} \cdot \left\lfloor \frac{\left\lfloor \frac{j}{i} \right\rfloor}{\left\lceil \frac{j}{i} \right\rceil} \right\rfloor \right)}\right\rfloor\right)\right\rceil\right)

Advertisements

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s